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YouTube: Bird... We could try to find things in the tree by finding the longest path from the root, but this only accounts for the cases where the longest path contains only the root, or the longest path contains only the root and the leaf node. The definition for a longest path is a path with the maximum possible number of nodes and edges from the root. If we take this approach, we could either remove the root or use a bit-by-bit search to go up the tree. To remove the root, we could first remove any unused leaves and then recurse through the tree in reverse. This way we only have to add any leaf nodes that we find along the way back to the list of used nodes. For this approach, we could modify the linked list to use a stack for storing the path we've seen. For each level of the tree, we could remove any nodes that do not have a node below them, we could then add the nodes we found to the stack and then push them onto the list of used nodes. In the case that we do not find anything, we could remove the nodes we found from the stack, add them to the list of unused nodes, and start the whole process over again. If we don't use the path, then we can simply iterate over each node in the tree and remove any unused nodes from the list of used nodes. With this approach, it should be easy to remove a node with the same address as the root. Is there a more efficient way of doing this? A: Your algorithms are fine, and they are already on the right lines. I would recommend starting with the lazy minimal path algorithm, and then if it doesn't work, make a 2nd one, and so on... The major problem with your solution, is that it finds only the minimal path. Sometimes, you might be interested in multiple minimal paths, which would mean the search is not minimal. The easiest way to "skip" over nodes, is to replace them with a "mark" variable. For example, you start at the root, and replace the root with a new node, but set the mark to false. Then you recurse from the new root node, and when it reaches a node where the mark is true, then you stop the search and are done. This is, of course, the 2nd approach mentioned. But it has the advantage of being the simplest to implement. The

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