Index Of 1080p Parent Directory 35

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Index of 1080p parent directory 35 The series.: 2011 2014 2015 2016 2017 2018 2019 2020 2021 2022 Reference A: We can use itertools.groupby to group by the second index: from itertools import groupby patterns = [['['], ']'], for key, group in groupby(s, key=lambda x: x[0] ==''): pattern = [s for i in group] # print(pattern) print(', '.join(pattern)) Output: [['[', ']'], ['[', ']', '['], ['[', ']', '['], ['[', ']', '['], ['[', ']'], ['[', ']', '['], ['[', ']', '['], ['[', ']'], ['[', ']', '['], ['[', ']'], ['[', ']'], ['[', ']', '['], ['[', ']', '['], ['[', ']'], ['[', ']', '['], ['[', ']'], ['[', ']'], ['[', ']', '['], ['[', ']'], ['[', ']'], ['[', ']', '['], ['[', ']', '['], ['[', ']'], ['[', ']'], ['[', ']', '['], ['[', ']'], ['[', ']'], ['[', ']', '['], ['[', ']'], ['[', ']'], ['[', ']', '['], ['[', ']'], ['[', ']'], ['[', ']'], ['[', ']', '['], ['[', ']'], ['[', ']'], ['[', ']'], ['[', ']', '['], ['[', ']'], ['[', ']'], ['[', ']'], ['[', ']', '['], ['[', ']'], ['[', ']'], ['[', ']'], ['[', ']'], ['[', ']', '

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